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1
JEE Main 2026 (Online) 22nd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Using a simple pendulum experiment $g$ is determind by measuring its time period $T$. Which of the following plots represent the correct relation between the pendulum length $L$ and time period $T$ ?
A
JEE Main 2026 (Online) 22nd January Evening Shift Physics - Simple Harmonic Motion Question 11 English Option 1
B
JEE Main 2026 (Online) 22nd January Evening Shift Physics - Simple Harmonic Motion Question 11 English Option 2
C
JEE Main 2026 (Online) 22nd January Evening Shift Physics - Simple Harmonic Motion Question 11 English Option 3
D
JEE Main 2026 (Online) 22nd January Evening Shift Physics - Simple Harmonic Motion Question 11 English Option 4
2
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad/s. The frequency of this simple harmonic oscillator is ______ Hz. [ take $\pi = \frac{22}{7}$ ]

A

88

B

14

C

28

D

176

3
JEE Main 2025 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A block of mass 2 kg is attached to one end of a massless spring whose other end is fixed at a wall. The spring-mass system moves on a frictionless horizontal table. The spring's natural length is 2 m and spring constant is 200 N/m. The block is pushed such that the length of the spring becomes 1 m and then released. At distance x m (x < 2) from the wall, the speed of the block will be

A

$10\left[1-(2-x)^2\right]^{\frac{1}{2}} \ m/s$

B

$10\left[1-(2-x)^2\right]^{\frac{3}{2}} \ m/s$

C

$10\left[1-(2-x)^2\right] \ m/s$

D

$10\left[1-(2-x)^2\right]^2 \ m/s$

4
JEE Main 2025 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Two simple pendulums having lengths $l_1$ and $l_2$ with negligible string mass undergo angular displacements $\theta_1$ and $\theta_2$, from their mean positions, respectively. If the angular accelerations of both pendulums are same, then which expression is correct?

A
$\theta_1 l_2=\theta_2 l_1$
B
$\theta_1 l_1=\theta_2 l_2$
C
$\theta_1 l_2^2=\theta_2 l_1^2$
D
$\theta_1 l_1^2=\theta_2 l_2^2$

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