1
JEE Main 2021 (Online) 27th August Morning Shift
+4
-1
The variation of displacement with time of a particle executing free simple harmonic motion is shown in the figure.

The potential energy U(x) versus time (t) plot of the particle is correctly shown in figure :
A
B
C
D
2
JEE Main 2021 (Online) 27th July Evening Shift
+4
-1
An object of mass 0.5 kg is executing simple harmonic motion. It amplitude is 5 cm and time period (T) is 0.2 s. What will be the potential energy of the object at an instant $$t = {T \over 4}s$$ starting from mean position. Assume that the initial phase of the oscillation is zero.
A
0.62 J
B
6.2 $$\times$$ 10$$-$$3 J
C
1.2 $$\times$$ 103 J
D
6.2 $$\times$$ 103 J
3
JEE Main 2021 (Online) 27th July Morning Shift
+4
-1
A particle starts executing simple harmonic motion (SHM) of amplitude 'a' and total energy E. At any instant, its kinetic energy is $${{3E} \over 4}$$ then its displacement 'y' is given by :
A
y = a
B
$$y = {a \over {\sqrt 2 }}$$
C
$$y = {{a\sqrt 3 } \over 2}$$
D
$$y = {a \over 2}$$
4
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.
A
$${1 \over 2}$$
B
$${3 \over 4}$$
C
$${1 \over 3}$$
D
$${1 \over 4}$$
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