1
JEE Main 2023 (Online) 1st February Evening Shift
+4
-1

Choose the correct length (L) versus square of the time period ($$\mathrm{T}^{2}$$) graph for a simple pendulum executing simple harmonic motion.

A
B
C
D
2
JEE Main 2023 (Online) 31st January Morning Shift
+4
-1

The maximum potential energy of a block executing simple harmonic motion is $$25 \mathrm{~J}$$. A is amplitude of oscillation. At $$\mathrm{A / 2}$$, the kinetic energy of the block is

A
9.75 J
B
37.5 J
C
18.75 J
D
12.5 J
3
JEE Main 2023 (Online) 30th January Evening Shift
+4
-1

For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1 \mathrm{~kg}$, the angular frequency is $\omega_{1}$. When the mass block is $2 \mathrm{~kg}$ the angular frequency is $\omega_{2}$. The ratio $\omega_{2} / \omega_{1}$ is

A
$1 / \sqrt{2}$
B
$1 / 2$
C
2
D
$\sqrt{2}$
4
JEE Main 2023 (Online) 25th January Evening Shift
+4
-1

A particle executes simple harmonic motion between $$x=-A$$ and $$x=+A$$. If time taken by particle to go from $$x=0$$ to $$\frac{A}{2}$$ is 2 s; then time taken by particle in going from $$x=\frac{A}{2}$$ to A is

A
4 s
B
1.5 s
C
3 s
D
2 s
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