1
JEE Main 2023 (Online) 25th January Evening Shift
+4
-1

A particle executes simple harmonic motion between $$x=-A$$ and $$x=+A$$. If time taken by particle to go from $$x=0$$ to $$\frac{A}{2}$$ is 2 s; then time taken by particle in going from $$x=\frac{A}{2}$$ to A is

A
4 s
B
1.5 s
C
3 s
D
2 s
2
JEE Main 2023 (Online) 25th January Morning Shift
+4
-1

T is the time period of simple pendulum on the earth's surface. Its time period becomes $$x$$ T when taken to a height R (equal to earth's radius) above the earth's surface. Then, the value of $$x$$ will be :

A
4
B
$$\frac{1}{2}$$
C
2
D
$$\frac{1}{4}$$
3
JEE Main 2022 (Online) 29th July Morning Shift
+4
-1

The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination $$\alpha$$, is given by :

A
$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \cos \alpha)}$$
B
$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \sin \alpha)}$$
C
$$2 \pi \sqrt{\mathrm{L} / \mathrm{g}}$$
D
$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \tan \alpha)}$$
4
JEE Main 2022 (Online) 28th July Evening Shift
+4
-1

Assume there are two identical simple pendulum clocks. Clock - 1 is placed on the earth and Clock - 2 is placed on a space station located at a height h above the earth surface. Clock - 1 and Clock - 2 operate at time periods 4 s and 6 s respectively. Then the value of h is -

(consider radius of earth $$R_{E}=6400 \mathrm{~km}$$ and $$\mathrm{g}$$ on earth $$10 \mathrm{~m} / \mathrm{s}^{2}$$ )

A
1200 km
B
1600 km
C
3200 km
D
4800 km
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