1
JEE Main 2023 (Online) 25th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A particle executes simple harmonic motion between $$x=-A$$ and $$x=+A$$. If time taken by particle to go from $$x=0$$ to $$\frac{A}{2}$$ is 2 s; then time taken by particle in going from $$x=\frac{A}{2}$$ to A is

A
4 s
B
1.5 s
C
3 s
D
2 s
2
JEE Main 2022 (Online) 29th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination $$\alpha$$, is given by :

A
$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \cos \alpha)}$$
B
$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \sin \alpha)}$$
C
$$2 \pi \sqrt{\mathrm{L} / \mathrm{g}}$$
D
$$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \tan \alpha)}$$
3
JEE Main 2022 (Online) 26th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be :

A
Circular
B
Elliptical
C
Sinusoidal
D
Straight line
4
JEE Main 2022 (Online) 25th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

JEE Main 2022 (Online) 25th July Morning Shift Physics - Simple Harmonic Motion Question 30 English

In figure $$(\mathrm{A})$$, mass '$$2 \mathrm{~m}^{\text {' }}$$ is fixed on mass '$$\mathrm{m}$$ ' which is attached to two springs of spring constant $$\mathrm{k}$$. In figure (B), mass '$$\mathrm{m}$$' is attached to two springs of spring constant '$$\mathrm{k}$$' and '$$2 \mathrm{k}^{\prime}$$. If mass '$$\mathrm{m}$$' in (A) and in (B) are displaced by distance '$$x^{\prime}$$ horizontally and then released, then time period $$\mathrm{T}_{1}$$ and $$\mathrm{T}_{2}$$ corresponding to $$(\mathrm{A})$$ and (B) respectively follow the relation.

A
$$ \frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\frac{3}{\sqrt{2}} $$
B
$$ \frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\sqrt{\frac{3}{2}} $$
C
$$ \frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\sqrt{\frac{2}{3}} $$
D
$$ \frac{T_{1}}{T_{2}}=\frac{\sqrt{2}}{3} $$
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