1
JEE Main 2021 (Online) 25th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.
A
$${1 \over 2}$$
B
$${3 \over 4}$$
C
$${1 \over 3}$$
D
$${1 \over 4}$$
2
JEE Main 2021 (Online) 22th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
T0 is the time period of a simple pendulum at a place. if the length of the pendulum is reduced to $${1 \over {16}}$$ times of its initial value, the modified time period is :
A
4 T0
B
$${1 \over {4}}$$ T0
C
T0
D
8$$\pi$$ T0
3
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
A particle is making simple harmonic motion along the X-axis. If at a distances x1 and x2 from the mean position the velocities of the particle are v1 and v2 respectively. The time period of its oscillation is given as :
A
$$T = 2\pi \sqrt {{{x_2^2 + x_1^2} \over {v_1^2 - v_2^2}}}$$
B
$$T = 2\pi \sqrt {{{x_2^2 + x_1^2} \over {v_1^2 + v_2^2}}}$$
C
$$T = 2\pi \sqrt {{{x_2^2 - x_1^2} \over {v_1^2 + v_2^2}}}$$
D
$$T = 2\pi \sqrt {{{x_2^2 - x_1^2} \over {v_1^2 - v_2^2}}}$$
4
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
The function of time representing a simple harmonic motion with a period of $${\pi \over \omega }$$ is :
A
cos($$\omega$$t) + cos(2$$\omega$$t) + cos(3$$\omega$$t)
B
sin2($$\omega$$t)
C
sin($$\omega$$t) + cos($$\omega$$t)
D
3cos$$\left( {{\pi \over 4} - 2\omega t} \right)$$
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