1
JEE Main 2025 (Online) 22nd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : A simple pendulum is taken to a planet of mass and radius, 4 times and 2 times, respectively, than the Earth. The time period of the pendulum remains same on earth and the planet.

Reason (R) : The mass of the pendulum remains unchanged at Earth and the other planet.

In the light of the above statements, choose the correct answer from the options given below :

A
Both (A) and (R) are true and (R) is the correct explanation of (A)
B
(A) is false but (R) is true
C
(A) is true but (R) is false
D
Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
2
JEE Main 2024 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A simple pendulum doing small oscillations at a place $$R$$ height above earth surface has time period of $$T_1=4 \mathrm{~s}$$. $$\mathrm{T}_2$$ would be it's time period if it is brought to a point which is at a height $$2 \mathrm{R}$$ from earth surface. Choose the correct relation [$$\mathrm{R}=$$ radius of earth] :

A
$$3 \mathrm{~T}_1=2 \mathrm{~T}_2$$
B
$$\mathrm{T}_1=\mathrm{T}_2$$
C
$$2 \mathrm{~T}_1=3 \mathrm{~T}_2$$
D
$$2 \mathrm{~T}_1=\mathrm{T}_2$$
3
JEE Main 2024 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In simple harmonic motion, the total mechanical energy of given system is $$E$$. If mass of oscillating particle $$P$$ is doubled then the new energy of the system for same amplitude is:

JEE Main 2024 (Online) 4th April Evening Shift Physics - Simple Harmonic Motion Question 15 English

A
$$E / \sqrt{2}$$
B
$$2 E$$
C
$$E \sqrt{2}$$
D
$$E$$
4
JEE Main 2024 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A simple pendulum of length $1 \mathrm{~m}$ has a wooden bob of mass $1 \mathrm{~kg}$. It is struck by a bullet of mass $10^{-2} \mathrm{~kg}$ moving with a speed of $2 \times 10^2 \mathrm{~ms}^{-1}$. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )
A
$0.20 \mathrm{~m}$
B
$0.40 \mathrm{~m}$
C
$0.30 \mathrm{~m}$
D
$0.35 \mathrm{~m}$
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