AIEEE 2005 | Simple Harmonic Motion Question 154 | Physics

In forced oscillation of a particle the amplitude is maximum for a frequency $${\omega _1}$$ of the force while the energy is maximum for a frequency $${\omega _2}$$ of the force; then

$${\omega _1} < {\omega _2}$$ when damping is small and $${\omega _1} > {\omega _2}$$ when damping is large

$${\omega _1} > {\omega _2}$$

$${\omega _1} = {\omega _2}$$

$${\omega _1} < {\omega _2}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

The bob of a simple pendulum executes simple harmonic motion in water with a period $$t,$$ while the period of oscillation of the bob is $${t_0}$$ in air. Neglecting frictional force of water and given that the density of the bob is $$\left( {4/3} \right) \times 1000\,\,kg/{m^3}.$$ What relationship between $$t$$ and $${t_0}$$ is true

$$t = 2{t_0}$$

$$t = {t_0}/2$$

$$t = {t_0}$$

$$t = 4{t_0}$$

AIEEE 2004

MCQ (Single Correct Answer)

-1

The total energy of particle, executing simple harmonic motion is

independent of $$x$$

$$ \propto \,{x^2}$$

$$ \propto \,x$$

$$ \propto \,{x^{1/2}}$$