JEE Main 2021 (Online) 26th February Evening Shift | Simple Harmonic Motion Question 49 | Physics

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JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

A particle executes S.H.M., the graph of velocity as a function of displacement is :

a parabola

a helix

an ellipse

a circle

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

Given below are two statements :

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are false

Statement I is false but Statement II is true

Both Statement I and Statement II are true

Statement I is true but Statement II is false

JEE Main 2021 (Online) 25th February Evening Shift

MCQ (Single Correct Answer)

-1

Y = A sin($$\omega$$t + $$\phi$$₀) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is $$Y = {A \over 2}$$ and it is moving along negative x-direction. Then the initial phase angle $$\phi$$₀ will be:

$${{5\pi } \over 6}$$

$${{\pi } \over 3}$$

$${{2\pi } \over 3}$$

$${{\pi } \over 6}$$

JEE Main 2021 (Online) 25th February Evening Shift

MCQ (Single Correct Answer)

-1

Two identical springs of spring constant '2k' are attached to a block of mass m and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. The time period of oscillations of this system is :

JEE Main 2021 (Online) 25th February Evening Shift Physics - Simple Harmonic Motion Question 55 English