JEE Main 2021 (Online) 26th February Evening Shift | Simple Harmonic Motion Question 91 | Physics

Given below are two statements :

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are false

Statement I is false but Statement II is true

Both Statement I and Statement II are true

Statement I is true but Statement II is false

JEE Main 2021 (Online) 26th February Morning Shift

MCQ (Single Correct Answer)

-1

Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance (R/2) from the earth's centre, where 'R' is the radius of the Earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time period :

$$2\pi \sqrt {{R \over g}} $$

$${g \over {2\pi R}}$$

$${{2\pi R} \over g}$$

$${1 \over {2\pi }}\sqrt {{g \over R}} $$

JEE Main 2021 (Online) 26th February Morning Shift

MCQ (Single Correct Answer)

-1

If two similar springs each of spring constant K₁ are joined in series, the new spring constant and time period would be changed by a factor :

$${1 \over 2},2\sqrt 2 $$

$${1 \over 4},2\sqrt 2 $$

$${1 \over 2},\sqrt 2 $$

$${1 \over 4},\sqrt 2 $$