1
JEE Main 2023 (Online) 8th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For particle P revolving round the centre O with radius of circular path $$\mathrm{r}$$ and angular velocity $$\omega$$, as shown in below figure, the projection of OP on the $$x$$-axis at time $$t$$ is

JEE Main 2023 (Online) 8th April Evening Shift Physics - Simple Harmonic Motion Question 19 English

A
$$x(t)=\operatorname{cos}\left(\omega t-\frac{\pi}{6} \omega\right)$$
B
$$x(t)=\operatorname{cos}(\omega t)$$
C
$$x(t)=r \cos \left(\omega t+\frac{\pi}{6}\right)$$
D
$$x(t)=r \sin \left(\omega t+\frac{\pi}{6}\right)$$
2
JEE Main 2023 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A mass $$m$$ is attached to two strings as shown in figure. The spring constants of two springs are $$\mathrm{K}_{1}$$ and $$\mathrm{K}_{2}$$. For the frictionless surface, the time period of oscillation of mass $$m$$ is :

JEE Main 2023 (Online) 6th April Morning Shift Physics - Simple Harmonic Motion Question 18 English

A
$$2\pi \sqrt {{m \over {{K_1} + {K_2}}}} $$
B
$$2\pi \sqrt {{m \over {{K_1} - {K_2}}}} $$
C
$${1 \over {2\pi }}\sqrt {{{{K_1} + {K_2}} \over m}} $$
D
$${1 \over {2\pi }}\sqrt {{{{K_1} - {K_2}} \over m}} $$
3
JEE Main 2023 (Online) 1st February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Choose the correct length (L) versus square of the time period ($$\mathrm{T}^{2}$$) graph for a simple pendulum executing simple harmonic motion.

A
JEE Main 2023 (Online) 1st February Evening Shift Physics - Simple Harmonic Motion Question 39 English Option 1
B
JEE Main 2023 (Online) 1st February Evening Shift Physics - Simple Harmonic Motion Question 39 English Option 2
C
JEE Main 2023 (Online) 1st February Evening Shift Physics - Simple Harmonic Motion Question 39 English Option 3
D
JEE Main 2023 (Online) 1st February Evening Shift Physics - Simple Harmonic Motion Question 39 English Option 4
4
JEE Main 2023 (Online) 31st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The maximum potential energy of a block executing simple harmonic motion is $$25 \mathrm{~J}$$. A is amplitude of oscillation. At $$\mathrm{A / 2}$$, the kinetic energy of the block is

A
9.75 J
B
37.5 J
C
18.75 J
D
12.5 J
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