1
JEE Main 2021 (Online) 16th March Morning Shift
MCQ (Single Correct Answer)
+4
-1
Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be :
A
$$\sqrt 3 T$$
B
$$\sqrt {{2 \over 3}} T$$
C
$${T \over {\sqrt 3 }}$$
D
$$\sqrt {{3 \over 2}} T$$
2
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
A particle executes S.H.M., the graph of velocity as a function of displacement is :
A
a parabola
B
a helix
C
an ellipse
D
a circle
3
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Given below are two statements :

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below :
A
Both Statement I and Statement II are false
B
Statement I is false but Statement II is true
C
Both Statement I and Statement II are true
D
Statement I is true but Statement II is false
4
JEE Main 2021 (Online) 25th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Y = A sin($$\omega$$t + $$\phi$$0) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is $$Y = {A \over 2}$$ and it is moving along negative x-direction. Then the initial phase angle $$\phi$$0 will be:
A
$${{5\pi } \over 6}$$
B
$${{\pi } \over 3}$$
C
$${{2\pi } \over 3}$$
D
$${{\pi } \over 6}$$
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