JEE Main 2021 (Online) 16th March Morning Shift | Simple Harmonic Motion Question 90 | Physics

Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be :

$$\sqrt 3 T$$

$$\sqrt {{2 \over 3}} T$$

$${T \over {\sqrt 3 }}$$

$$\sqrt {{3 \over 2}} T$$

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

A particle executes S.H.M., the graph of velocity as a function of displacement is :

a parabola

a helix

an ellipse

a circle

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

Given below are two statements :

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are false

Statement I is false but Statement II is true

Both Statement I and Statement II are true

Statement I is true but Statement II is false

JEE Main 2021 (Online) 26th February Morning Shift

MCQ (Single Correct Answer)

-1

Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance (R/2) from the earth's centre, where 'R' is the radius of the Earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time period :

$$2\pi \sqrt {{R \over g}} $$

$${g \over {2\pi R}}$$

$${{2\pi R} \over g}$$

$${1 \over {2\pi }}\sqrt {{g \over R}} $$

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