JEE Main 2021 (Online) 16th March Morning Shift | Simple Harmonic Motion Question 48 | Physics

JEE Main 2021 (Online) 16th March Morning Shift

MCQ (Single Correct Answer)

-1

Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be :

$$\sqrt 3 T$$

$$\sqrt {{2 \over 3}} T$$

$${T \over {\sqrt 3 }}$$

$$\sqrt {{3 \over 2}} T$$

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

A particle executes S.H.M., the graph of velocity as a function of displacement is :

a parabola

a helix

an ellipse

a circle

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

Given below are two statements :

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are false

Statement I is false but Statement II is true

Both Statement I and Statement II are true

Statement I is true but Statement II is false

JEE Main 2021 (Online) 25th February Evening Shift

MCQ (Single Correct Answer)

-1

Y = A sin($$\omega$$t + $$\phi$$₀) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is $$Y = {A \over 2}$$ and it is moving along negative x-direction. Then the initial phase angle $$\phi$$₀ will be:

$${{5\pi } \over 6}$$

$${{\pi } \over 3}$$

$${{2\pi } \over 3}$$

$${{\pi } \over 6}$$

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