1
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A block of mass 0.1 kg is connected to an elastic spring of spring constant 640 Nm−1 and oscillates in a damping medium of damping constant 10−2 kg s−1 . The system dissipates its energy gradually. The time taken for its mechanical energy of vibration to drop to half of its initial value, is closest to :
A
2 s
B
3.5 s
C
5 s
D
7 s
2
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A 1 kg block attached to a spring vibrates with a frequency of 1 Hz on a frictionless horizontal table. Two springs identical to the original spring are attached in parallel to an 8 kg block placed on the same table. So, the frequency of vibration of the 8 kg block is :
A
$${1 \over 4}Hz$$
B
$${1 \over {2\sqrt 2 }}Hz$$
C
$${1 \over 2}Hz$$
D
$$2$$ $$Hz$$
3
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s−1 . At, t = 0 the displacement is 5 m. What is the maximum acceleration ? The initial phase is $${\pi \over 4}$$.
A
500 m/s2
B
500 $$\sqrt 2 m/$$ s2
C
750 m/s2
D
750 $$\sqrt 2 $$m / s2
4
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is executing simple harmonic motion with a time period T. At time t = 0, it is at its position of equilibrium. The kinetic energy – time graph of the particle will look like:
A
JEE Main 2017 (Offline) Physics - Simple Harmonic Motion Question 116 English Option 1
B
JEE Main 2017 (Offline) Physics - Simple Harmonic Motion Question 116 English Option 2
C
JEE Main 2017 (Offline) Physics - Simple Harmonic Motion Question 116 English Option 3
D
JEE Main 2017 (Offline) Physics - Simple Harmonic Motion Question 116 English Option 4
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