JEE Main 2021 (Online) 16th March Evening Shift | Simple Harmonic Motion Question 79 | Physics

Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass = 500g, Decay constant = 20 g/s then how much time is required for the amplitude of the system to drop to drop to half of its initial value? (ln 2 = 0.693)

17.32 s

34.65 s

0.034 s

15.01 s

JEE Main 2021 (Online) 16th March Morning Shift

MCQ (Single Correct Answer)

-1

Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be :

$$\sqrt 3 T$$

$$\sqrt {{2 \over 3}} T$$

$${T \over {\sqrt 3 }}$$

$$\sqrt {{3 \over 2}} T$$

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

A particle executes S.H.M., the graph of velocity as a function of displacement is :

a parabola

a helix

an ellipse

a circle

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

Given below are two statements :

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are false

Statement I is false but Statement II is true

Both Statement I and Statement II are true

Statement I is true but Statement II is false

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