JEE Main 2021 (Online) 25th February Morning Shift | Simple Harmonic Motion Question 89 | Physics

In the given figure, a body of mass M is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant k, the frequency of oscillation of given body is :

JEE Main 2021 (Online) 24th February Evening Shift Physics - Simple Harmonic Motion Question 92 English

JEE Main 2021 (Online) 24th February Evening Shift Physics - Simple Harmonic Motion Question 92 English

$${1 \over {2\pi }}\sqrt {{{2k} \over {Mg\sin \alpha }}} $$

$${1 \over {2\pi }}\sqrt {{k \over {Mg\sin \alpha }}} $$

$${1 \over {2\pi }}\sqrt {{{2k} \over M}} $$

$${1 \over {2\pi }}\sqrt {{k \over {2M}}} $$

JEE Main 2021 (Online) 24th February Evening Shift

MCQ (Single Correct Answer)

-1

When a particle executes SHM, the nature of graphical representation of velocity as a function of displacement is :

circular

straight line

parabolic

elliptical

JEE Main 2021 (Online) 24th February Evening Shift

MCQ (Single Correct Answer)

-1

The period of oscillation of a simple pendulum is $$T = 2\pi \sqrt {{L \over g}} $$. Measured value of 'L' is 1.0 m from meter scale having a minimum division of 1 mm and time of one complete oscillation is 1.95 s measured from stopwatch of 0.01 s resolution. The percentage error in the determination of 'g' will be :

1.30%

1.33%

1.13%

1.03%

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