1
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Three different processes that can occur in an ideal monoatomic gas are shown in the P vs V diagram. The paths are labelled as A $$ \to $$ B, A $$ \to $$ C and A $$ \to $$ D. The change in internal energies during these process are taken as EAB, EAC and EAD and the work done as WAB, WAC and WAD.
The correct relation between these parameters are : JEE Main 2020 (Online) 5th September Morning Slot Physics - Heat and Thermodynamics Question 237 English
A
EAB < EAC < EAD, WAB > 0, WAC > WAD
B
EAB = EAC = EAD, WAB > 0, WAC = 0, WAD < 0
C
EAB > EAC > EAD, WAB < WAC < WAD
D
EAB = EAC < EAD, WAB > 0, WAC = 0, WAD < 0
2
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Number of molecules in a volume of 4 cm3 of a perfect monoatomic gas at some temperature T and at a pressure of 2 cm of mercury is close to?
(Given, mean kinetic energy of a molecule
(at T) is 4 $$ \times $$ 10–14 erg, g = 980 cm/s2, density of
mercury = 13.6 g/cm3)
A
5.8 $$ \times $$ 1018
B
4.0 $$ \times $$ 1016
C
5.8 $$ \times $$ 1016
D
4.0 $$ \times $$ 1018
3
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Match the thermodynamic processes taking place in a system with the correct conditions. In the table : $$\Delta $$Q is the heat supplied, $$\Delta $$W is the work done and $$\Delta $$U is change in internal energy of the system.

Process Condition
(I) Adiabatic (1) $$\Delta $$W = 0
(II) Isothermal (2) $$\Delta $$Q = 0
(III) Isochoric (3) $$\Delta $$U $$ \ne $$ 0, $$\Delta $$W $$ \ne $$ 0, $$\Delta $$Q $$ \ne $$ 0
(IV) Isobaric (4) $$\Delta $$U = 0
A
(I) - (1), (II) - (1), (III) - (2), (IV) - (3)
B
(I) - (2), (II) - (4), (III) - (1), (IV) - (3)
C
(I) - (1), (II) - (2), (III) - (4), (IV) - (4)
D
(I) - (2), (II) - (1), (III) - (4), (IV) - (3)
4
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The specific heat of water
= 4200 J kg-1K-1 and the latent heat of
ice = 3.4 $$ \times $$ 105 J kg–1. 100 grams of ice at
0oC is placed in 200 g of water at 25oC. The
amount of ice that will melt as the temperature
of water reaches 0oC is close to (in grams) :
A
63.8
B
61.7
C
69.3
D
64.6
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