The material filled between the plates of a parallel plate capacitor has resistivity 200 $$\Omega$$m. The value of capacitance of the capacitor is 2 pF. If a potential difference of 40 V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is : (given the value of relative permittivity of material is 50)

Match List I with List II.

	List - I		List - II
(a)	Capacitance, C	(i)	$${M^1}{L^1}{T^{ - 3}}{A^{ - 1}}$$
(b)	Permittivity of free space, $${\varepsilon _0}$$	(ii)	$${M^{ - 1}}{L^{ - 3}}{T^4}{A^2}$$
(c)	Permeability of free space, $${\mu _0}$$	(iii)	$${M^{ - 1}}{L^{ - 2}}{T^4}{A^2}$$
(d)	Electric field, E	(iv)	$${M^1}{L^1}{T^{ - 2}}{A^{ - 2}}$$

Choose the correct answer from the options given below

A simple pendulum of mass 'm', length 'l' and charge '+ q' suspended in the electric field produced by two conducting parallel plates as shown. The value of deflection of pendulum in equilibrium position will be

A capacitor of capacitance C = 1 $$\mu$$F is suddenly connected to a battery of 100 volt through a resistance R = 100 $$\Omega$$. The time taken for the capacitor to be charged to get 50 V is :

[Take ln 2 = 0.69]