1
JEE Main 2018 (Online) 15th April Evening Slot
+4
-1
A parallel plate capacitor with area 200 cm2 and separation between the plates 1.5 cm, is connected across a battery of emf V. If the force of attraction between the plates is $$25 \times {10^{ - 6}}N,$$ the value of V is approximately : $$\left( {{ \in _o} = 8.85 \times {{10}^{ - 12}}{{{C^2}} \over {N.{m^2}}}} \right)$$
A
250 V
B
100 V
C
300 V
D
150 V
2
JEE Main 2018 (Online) 15th April Evening Slot
+4
-1
A capacitor C1 = 1.0 $$\mu$$F is charged up to a voltage V = 60 V by connecting it to battery B through switch (1). Now C1 is disconnected from battery and connected to a circuit consisting of two uncharged capacitors $${C_2} = 3.0\mu F$$ and C3 = 6.0 $$\mu$$F through switch (2), as shown in the figure. The sum of final charges on C2 and C3 is :
A
40 $$\mu$$C
B
36 $$\mu$$C
C
20 $$\mu$$C
D
54 $$\mu$$C
3
JEE Main 2018 (Online) 15th April Morning Slot
+4
-1
The equivalent capacitance between $$A$$ and $$B$$ in the circuit given below, is :

A
$$2.4\,\mu F$$
B
$$4.9\,\mu F$$
C
$$3.6\,\mu F$$
D
$$5.4\,\mu F$$
4
JEE Main 2017 (Online) 9th April Morning Slot
+4
-1
A combination of parallel plate capacitors is maintained at a certain potential difference.

When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm. Find the dielectric constant of the slab.
A
3
B
4
C
5
D
6
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