Calculate the amount of charge on capacitor of 4$$\mu$$F. The internal resistance of battery is 1$$\Omega$$ :

A parallel plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K₁ and K₂ of same area A/2 and thickness d/2 are inserted in the space between the plates. The capacitance of the capacitor will be given by:

The material filled between the plates of a parallel plate capacitor has resistivity 200 $$\Omega$$m. The value of capacitance of the capacitor is 2 pF. If a potential difference of 40 V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is : (given the value of relative permittivity of material is 50)

Match List I with List II.

	List - I		List - II
(a)	Capacitance, C	(i)	$${M^1}{L^1}{T^{ - 3}}{A^{ - 1}}$$
(b)	Permittivity of free space, $${\varepsilon _0}$$	(ii)	$${M^{ - 1}}{L^{ - 3}}{T^4}{A^2}$$
(c)	Permeability of free space, $${\mu _0}$$	(iii)	$${M^{ - 1}}{L^{ - 2}}{T^4}{A^2}$$
(d)	Electric field, E	(iv)	$${M^1}{L^1}{T^{ - 2}}{A^{ - 2}}$$

Choose the correct answer from the options given below