JEE Main 2020 (Online) 8th January Evening Slot | Capacitor Question 121 | Physics

JEE Main 2020 (Online) 8th January Evening Slot

MCQ (Single Correct Answer)

-1

A capacitor is made of two square plates each of side 'a' making a very small angle $$\alpha $$ between them, as shown in figure. The capacitance will be close to : JEE Main 2020 (Online) 8th January Evening Slot Physics - Capacitor Question 122 English

JEE Main 2020 (Online) 8th January Evening Slot Physics - Capacitor Question 122 English

$${{{\varepsilon _0}{a^2}} \over d}\left( {1 + {{\alpha a} \over {d}}} \right)$$

$${{{\varepsilon _0}{a^2}} \over d}\left( {1 - {{\alpha a} \over {4d}}} \right)$$

$${{{\varepsilon _0}{a^2}} \over d}\left( {1 - {{\alpha a} \over {2d}}} \right)$$

$${{{\varepsilon _0}{a^2}} \over d}\left( {1 - {{3\alpha a} \over {2d}}} \right)$$

JEE Main 2020 (Online) 8th January Morning Slot

MCQ (Single Correct Answer)

-1

Effective capacitance of parallel combination of two capacitors C₁ and C₂ is 10 μF. When these capacitors are individually connected to a voltage source of 1V, the energy stored in the capacitor C₂ is 4 times that of C₁. If these capacitors are connected in series, their effective capacitance will be :

4.2 μF

8.4 μF

1.6 μF

3.2 μF

JEE Main 2020 (Online) 7th January Morning Slot

MCQ (Single Correct Answer)

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JEE Main 2020 (Online) 7th January Morning Slot Physics - Capacitor Question 125 English

A parallel plate capacitor has plates of area A separated by distance 'd' between them. It is filled with a dielectric which has a dielectric constant that varies as k(x) = K(1 + $$\alpha $$x) where 'x' is the distance measured from one of the plates. If (ad) << 1, the total capacitance of the system is best given by the expression :

$${{A{ \in _0}K} \over d}\left( {1 + {{\left( {{{\alpha d} \over 2}} \right)}^2}} \right)$$

$${{A{ \in _0}K} \over d}\left( {1 + {{\alpha d} \over 2}} \right)$$

$${{A{ \in _0}K} \over d}\left( {1 + {{{\alpha ^2}{d^2}} \over 2}} \right)$$

$${{A{ \in _0}K} \over d}\left( {1 + \alpha d} \right)$$

JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

In the given circuit, the charge on 4 $$\mu $$F capacitor will be : JEE Main 2019 (Online) 12th April Evening Slot Physics - Capacitor Question 126 English

5.4 $$\mu $$C

9.6 $$\mu $$C

13.4 $$\mu $$C

24 $$\mu $$C

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