1
JEE Main 2021 (Online) 27th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be :

(Given area of plate = A)

JEE Main 2021 (Online) 27th July Morning Shift Physics - Capacitor Question 70 English
A
$${{15} \over {34}}{{K{\varepsilon _0}A} \over d}$$
B
$${{15} \over 6}{{K{\varepsilon _0}A} \over d}$$
C
$${{25} \over 6}{{K{\varepsilon _0}A} \over d}$$
D
$${9 \over 6}{{K{\varepsilon _0}A} \over d}$$
2
JEE Main 2021 (Online) 27th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors will now be :
A
$${V \over {K + 2}}$$
B
$${V \over K}$$
C
$${{3V} \over {K + 2}}$$
D
$${{3V} \over K}$$
3
JEE Main 2021 (Online) 25th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
If qf is the free charge on the capacitor plates and qb is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then bound charge qb an be expressed as :
A
$${q_b} = {q_f}\left( {1 - {1 \over {\sqrt k }}} \right)$$
B
$${q_b} = {q_f}\left( {1 - {1 \over k}} \right)$$
C
$${q_b} = {q_f}\left( {1 + {1 \over {\sqrt k }}} \right)$$
D
$${q_b} = {q_f}\left( {1 + {1 \over k}} \right)$$
4
JEE Main 2021 (Online) 25th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A parallel plate capacitor with plate area 'A' and distance of separation 'd' is filled with a dielectric. What is the capacity of the capacitor when permittivity of the dielectric varies as :

$$\varepsilon (x) = {\varepsilon _0} + kx$$, for $$\left( {0 < x \le {d \over 2}} \right)$$

$$\varepsilon (x) = {\varepsilon _0} + k(d - x)$$, for $$\left( {{d \over 2} \le x \le d} \right)$$
A
$${\left( {{\varepsilon _0} + {{kd} \over 2}} \right)^{2/kA}}$$
B
$${{kA} \over {2\ln \left( {{{2{\varepsilon _0} + kd} \over {2{\varepsilon _0}}}} \right)}}$$
C
0
D
$${{kA} \over 2}\ln \left( {{{2{\varepsilon _0}} \over {2{\varepsilon _0} - kd}}} \right)$$
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