JEE Main 2024 (Online) 1st February Morning Shift | Capacitor Question 38 | Physics

Two identical capacitors have same capacitance $C$. One of them is charged to the potential $V$ and other to the potential $2 \mathrm{~V}$. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is :

$\frac{1}{4} \mathrm{CV}^2$

$\frac{3}{4} \mathrm{CV}^2$

$\frac{1}{2} \mathrm{CV}^2$

$2 \mathrm{CV}^2$

JEE Main 2023 (Online) 13th April Evening Shift

MCQ (Single Correct Answer)

-1

In the network shown below, the charge accumulated in the capacitor in steady state will be:

JEE Main 2023 (Online) 13th April Evening Shift Physics - Capacitor Question 54 English

10.3 $$\mu$$C

7.2 $$\mu$$C

4.8 $$\mu$$C

12 $$\mu$$C

JEE Main 2023 (Online) 11th April Evening Shift

MCQ (Single Correct Answer)

-1

A capacitor of capacitance $$\mathrm{C}$$ is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is :

Zero

$$\frac{C V}{\varepsilon_{0}}$$

$$\frac{C V}{2 \varepsilon_{0}}$$

$$\frac{2 C V}{\varepsilon_{0}}$$

JEE Main 2023 (Online) 11th April Morning Shift

MCQ (Single Correct Answer)

-1

A parallel plate capacitor of capacitance $$2 \mathrm{~F}$$ is charged to a potential $$\mathrm{V}$$, The energy stored in the capacitor is $$E_{1}$$. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is $$\mathrm{E}_{2}$$. The ratio $$\mathrm{E}_{2} / \mathrm{E}_{1}$$ is :

1 : 2

2 : 3

2 : 1

1 : 4

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