1
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1

A capacitor of capacitance $$\mathrm{C}$$ is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is :

A
Zero
B
$$\frac{C V}{\varepsilon_{0}}$$
C
$$\frac{C V}{2 \varepsilon_{0}}$$
D
$$\frac{2 C V}{\varepsilon_{0}}$$
2
JEE Main 2023 (Online) 11th April Morning Shift
+4
-1

A parallel plate capacitor of capacitance $$2 \mathrm{~F}$$ is charged to a potential $$\mathrm{V}$$, The energy stored in the capacitor is $$E_{1}$$. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is $$\mathrm{E}_{2}$$. The ratio $$\mathrm{E}_{2} / \mathrm{E}_{1}$$ is :

A
1 : 2
B
2 : 3
C
2 : 1
D
1 : 4
3
JEE Main 2023 (Online) 10th April Evening Shift
+4
-1

The distance between two plates of a capacitor is $$\mathrm{d}$$ and its capacitance is $$\mathrm{C}_{1}$$, when air is the medium between the plates. If a metal sheet of thickness $$\frac{2 d}{3}$$ and of the same area as plate is introduced between the plates, the capacitance of the capacitor becomes $$\mathrm{C}_{2}$$. The ratio $$\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$$ is

A
1 : 1
B
3 : 1
C
2 : 1
D
4 : 1
4
JEE Main 2023 (Online) 10th April Morning Shift
+4
-1

The equivalent capacitance of the combination shown is :

A
$$\frac{C}{2}$$
B
4C
C
$$\frac{5}{3}$$C
D
2C
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