JEE Main 2020 (Online) 5th September Morning Slot | Capacitor Question 60 | Physics

JEE Main 2020 (Online) 5th September Morning Slot

MCQ (Single Correct Answer)

-1

Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is :

Zero

$${3 \over 2}C{V^2}$$

$${9 \over 2}C{V^2}$$

$${{25} \over 6}C{V^2}$$

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

A capacitor C is fully charged with voltage V₀. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance $${C \over 2}$$. The energy loss in the process after the charge is distributed between the two capacitors is :

$${1 \over 2}CV_0^2$$

$${1 \over 4}CV_0^2$$

$${1 \over 3}CV_0^2$$

$${1 \over 6}CV_0^2$$

JEE Main 2020 (Online) 3rd September Morning Slot

MCQ (Single Correct Answer)

-1

In the circuit shown in the figure, the total charge is 750 $$\mu $$C and the voltage across capacitor C₂ is 20 V. Then the charge on capacitor C₂ is : JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 62 English

JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 62 English

160 $$\mu $$C

450 $$\mu $$C

590 $$\mu $$C

650 $$\mu $$C

JEE Main 2020 (Online) 2nd September Evening Slot

MCQ (Single Correct Answer)

-1

A 10 $$\mu $$F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is :

20 $$\mu $$F

15 $$\mu $$F

10 $$\mu $$F

30 $$\mu $$F

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