JEE Main 2021 (Online) 27th July Evening Shift | Capacitor Question 82 | Physics

JEE Main 2021 (Online) 27th July Evening Shift

MCQ (Single Correct Answer)

-1

Match List I with List II.

	List - I		List - II
(a)	Capacitance, C	(i)	$${M^1}{L^1}{T^{ - 3}}{A^{ - 1}}$$
(b)	Permittivity of free space, $${\varepsilon _0}$$	(ii)	$${M^{ - 1}}{L^{ - 3}}{T^4}{A^2}$$
(c)	Permeability of free space, $${\mu _0}$$	(iii)	$${M^{ - 1}}{L^{ - 2}}{T^4}{A^2}$$
(d)	Electric field, E	(iv)	$${M^1}{L^1}{T^{ - 2}}{A^{ - 2}}$$

Choose the correct answer from the options given below

(a) $$\to$$ (iii), (b) $$\to$$ (ii), (c) $$\to$$ (iv), (d) $$\to$$ (i)

(a) $$\to$$ (iii), (b) $$\to$$ (iv), (c) $$\to$$ (ii), (d) $$\to$$ (i)

(a) $$\to$$ (iv), (b) $$\to$$ (ii), (c) $$\to$$ (iii), (d) $$\to$$ (i)

(a) $$\to$$ (iv), (b) $$\to$$ (iii), (c) $$\to$$ (ii), (d) $$\to$$ (i)

JEE Main 2021 (Online) 27th July Evening Shift

MCQ (Single Correct Answer)

-1

A simple pendulum of mass 'm', length 'l' and charge '+ q' suspended in the electric field produced by two conducting parallel plates as shown. The value of deflection of pendulum in equilibrium position will be

JEE Main 2021 (Online) 27th July Evening Shift Physics - Capacitor Question 83 English

JEE Main 2021 (Online) 27th July Evening Shift Physics - Capacitor Question 83 English

$${\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_1}({V_2} - {V_1})} \over {({C_1} + {C_2})(d - t)}}} \right]$$

$${\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_2}({V_2} - {V_1})} \over {({C_1} + {C_2})(d - t)}}} \right]$$

$${\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_2}({V_1} + {V_2})} \over {({C_1} + {C_2})(d - t)}}} \right]$$

$${\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_1}({V_1} + {V_2})} \over {({C_1} + {C_2})(d - t)}}} \right]$$

JEE Main 2021 (Online) 27th July Morning Shift

MCQ (Single Correct Answer)

-1

JEE Main 2021 (Online) 27th July Morning Shift Physics - Capacitor Question 85 English

A capacitor of capacitance C = 1 $$\mu$$F is suddenly connected to a battery of 100 volt through a resistance R = 100 $$\Omega$$. The time taken for the capacitor to be charged to get 50 V is :

[Take ln 2 = 0.69]

1.44 $$\times$$ 10^$$-$$4 s

3.33 $$\times$$ 10^$$-$$4 s

0.69 $$\times$$ 10^$$-$$4 s

0.30 $$\times$$ 10^$$-$$4 s

JEE Main 2021 (Online) 27th July Morning Shift

MCQ (Single Correct Answer)

-1

In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be :

(Given area of plate = A)

JEE Main 2021 (Online) 27th July Morning Shift Physics - Capacitor Question 86 English

JEE Main 2021 (Online) 27th July Morning Shift Physics - Capacitor Question 86 English

$${{15} \over {34}}{{K{\varepsilon _0}A} \over d}$$

$${{15} \over 6}{{K{\varepsilon _0}A} \over d}$$

$${{25} \over 6}{{K{\varepsilon _0}A} \over d}$$

$${9 \over 6}{{K{\varepsilon _0}A} \over d}$$

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