1
JEE Main 2019 (Online) 8th April Morning Slot
+4
-1
Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of 106 V/m. The plate area is 10–4 m2. What is the dielectric constant is the capacitance is 15 pF? (given $$\varepsilon$$0 = 8.86 × 10–12 C2/Nm2)
A
8.5
B
4.5
C
3.8
D
6.2
2
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
A parallel plate capacitor with plates of area 1 m2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate is :

(Take $$\varepsilon$$0 = 8.85 $$\times$$ 10$$-$$12 $${{{C^2}} \over {N - {m^2}}}$$)
A
9.85 $$\times$$ 10–10 C
B
8.85 $$\times$$ 10–10 C
C
6.85 $$\times$$ 10–10 C
D
7.85 × 10–10 C
3
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
The charge on a capacitor plate in a circuit, as a function of time, is shown in the figure :

When is the value of current at t = 4 s ?
A
zero
B
1.5 $$\mu$$A
C
2 $$\mu$$A
D
3 $$\mu$$A
4
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
In the circuit shown, find C if the effective capacitance of the whole circuit is to be 0.5 $$\mu$$F. All values in the circuit are in $$\mu$$F.

A
$${6 \over 5}\mu F$$
B
$${7 \over 11}\mu F$$
C
4$$\mu$$F
D
$${7 \over 10}\mu F$$
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