JEE Main 2021 (Online) 26th February Morning Shift | Capacitor Question 81 | Physics

Consider the combination of 2 capacitors C₁ and C₂ with C₂ > C₁, when connected in parallel, the equivalent capacitance is $${{15} \over 4}$$ times the equivalent capacitance of the same connected in series. Calculate the ratio of capacitors, $${{{C_2}} \over {{C_1}}}$$.

$${{15} \over {11}}$$

No Solutions

$${{29} \over {15}}$$

$${{15} \over {4}}$$

JEE Main 2021 (Online) 25th February Evening Shift

MCQ (Single Correct Answer)

-1

An electron with kinetic energy K₁ enters between parallel plates of a capacitor at an angle '$$\alpha$$' with the plates. It leaves the plates at angle '$$\beta$$' with kinetic energy K₂. Then the ratio of kinetic energies K₁ : K₂ will be :

$${{{{\cos }^2}\beta } \over {{{\cos }^2}\alpha }}$$

$${{\cos \beta } \over {\cos \alpha }}$$

$${{{{\sin }^2}\beta } \over {{{\cos }^2}\alpha }}$$

$${{\cos \beta } \over {\sin \alpha }}$$

JEE Main 2021 (Online) 24th February Morning Shift

MCQ (Single Correct Answer)

-1

Two equal capacitors are first connected in series and then in parallel. The ratio of the equivalent capacities in the two cases will be :

4 : 1

1 : 2

2 : 1

1 : 4