JEE Main 2019 (Online) 10th April Morning Slot | Capacitor Question 99 | Physics

Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are : JEE Main 2019 (Online) 10th April Morning Slot Physics - Capacitor Question 100 English

JEE Main 2019 (Online) 10th April Morning Slot Physics - Capacitor Question 100 English

40 $$\mu $$F and 10 $$\mu $$F

60 $$\mu $$F and 40 $$\mu $$F

20 $$\mu $$F and 30 $$\mu $$F

50 $$\mu $$F and 30 $$\mu $$F

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

The parallel combination of two air filled parallel plate capacitors of capacitance C and nC is connected to a battery of voltage, V. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitor. The new potential difference of the combined system is :-

$${V \over {K + n}}$$

$${{(n+1)V} \over {K + n}}$$

$${{nV} \over {K + n}}$$

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

A capacitor with capacitance 5μF is charged to 5μC. If the plates are pulled apart to reduce the capacitance to 2μF, how much work is done ?

2.16 × 10^–6 J

2.55 × 10^–6 J

3.75 × 10^–6 J

6.25 × 10^–6 J

JEE Main 2019 (Online) 9th April Morning Slot