JEE Main 2020 (Online) 5th September Evening Slot | Capacitor Question 86 | Physics

In the circuit shown, charge on the 5 $$\mu $$F capacitor is :

JEE Main 2020 (Online) 5th September Evening Slot Physics - Capacitor Question 85 English

5.45 $$\mu $$C

18.00 $$\mu $$C

10.90 $$\mu $$C

16.36 $$\mu $$C

JEE Main 2020 (Online) 5th September Morning Slot

MCQ (Single Correct Answer)

-1

Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is :

Zero

$${3 \over 2}C{V^2}$$

$${9 \over 2}C{V^2}$$

$${{25} \over 6}C{V^2}$$

JEE Main 2020 (Online) 4th September Evening Slot

MCQ (Single Correct Answer)

-1

A capacitor C is fully charged with voltage V₀. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance $${C \over 2}$$. The energy loss in the process after the charge is distributed between the two capacitors is :

$${1 \over 2}CV_0^2$$

$${1 \over 4}CV_0^2$$

$${1 \over 3}CV_0^2$$

$${1 \over 6}CV_0^2$$

JEE Main 2020 (Online) 3rd September Morning Slot

MCQ (Single Correct Answer)

-1

In the circuit shown in the figure, the total charge is 750 $$\mu $$C and the voltage across capacitor C₂ is 20 V. Then the charge on capacitor C₂ is : JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 89 English