1
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A capacitor C is fully charged with voltage V0. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance $${C \over 2}$$. The energy loss in the process after the charge is distributed between the two capacitors is :
A
$${1 \over 2}CV_0^2$$
B
$${1 \over 4}CV_0^2$$
C
$${1 \over 3}CV_0^2$$
D
$${1 \over 6}CV_0^2$$
2
JEE Main 2020 (Online) 3rd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the circuit shown in the figure, the total charge is 750 $$\mu $$C and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is : JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 84 English
A
160 $$\mu $$C
B
450 $$\mu $$C
C
590 $$\mu $$C
D
650 $$\mu $$C
3
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A 10 $$\mu $$F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is :
A
20 $$\mu $$F
B
15 $$\mu $$F
C
10 $$\mu $$F
D
30 $$\mu $$F
4
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A capacitor is made of two square plates each of side 'a' making a very small angle $$\alpha $$ between them, as shown in figure. The capacitance will be close to : JEE Main 2020 (Online) 8th January Evening Slot Physics - Capacitor Question 89 English
A
$${{{\varepsilon _0}{a^2}} \over d}\left( {1 + {{\alpha a} \over {d}}} \right)$$
B
$${{{\varepsilon _0}{a^2}} \over d}\left( {1 - {{\alpha a} \over {4d}}} \right)$$
C
$${{{\varepsilon _0}{a^2}} \over d}\left( {1 - {{\alpha a} \over {2d}}} \right)$$
D
$${{{\varepsilon _0}{a^2}} \over d}\left( {1 - {{3\alpha a} \over {2d}}} \right)$$
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