1
JEE Main 2019 (Online) 10th April Evening Slot
+4
-1
A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by :
A
$$2\pi \sqrt {{L \over {\sqrt {{g^2} - {{{q^2}{E^2}} \over {{m^2}}}} }}}$$
B
$$2\pi \sqrt {{L \over {\left( {g + {{qE} \over m}} \right)}}}$$
C
$$2\pi \sqrt {{L \over {\sqrt {{g^2} + {{{q^2}{E^2}} \over {{m^2}}}} }}}$$
D
$$2\pi \sqrt {{L \over {\left( {g - {{qE} \over m}} \right)}}}$$
2
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are :
A
40 $$\mu$$F and 10 $$\mu$$F
B
60 $$\mu$$F and 40 $$\mu$$F
C
20 $$\mu$$F and 30 $$\mu$$F
D
50 $$\mu$$F and 30 $$\mu$$F
3
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
The parallel combination of two air filled parallel plate capacitors of capacitance C and nC is connected to a battery of voltage, V. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitor. The new potential difference of the combined system is :-
A
V
B
$${V \over {K + n}}$$
C
$${{(n+1)V} \over {K + n}}$$
D
$${{nV} \over {K + n}}$$
4
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
Determine the charge on the capacitor in the following circuit :
A
200μC
B
2μC
C
10μC
D
60μC
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