JEE Main 2019 (Online) 10th April Evening Slot | Capacitor Question 99 | Physics

A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by : JEE Main 2019 (Online) 10th April Evening Slot Physics - Capacitor Question 100 English

JEE Main 2019 (Online) 10th April Evening Slot Physics - Capacitor Question 100 English

$$2\pi \sqrt {{L \over {\sqrt {{g^2} - {{{q^2}{E^2}} \over {{m^2}}}} }}} $$

$$2\pi \sqrt {{L \over {\left( {g + {{qE} \over m}} \right)}}} $$

$$2\pi \sqrt {{L \over {\sqrt {{g^2} + {{{q^2}{E^2}} \over {{m^2}}}} }}} $$

$$2\pi \sqrt {{L \over {\left( {g - {{qE} \over m}} \right)}}} $$

JEE Main 2019 (Online) 10th April Morning Slot

MCQ (Single Correct Answer)

-1

Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are : JEE Main 2019 (Online) 10th April Morning Slot Physics - Capacitor Question 101 English

JEE Main 2019 (Online) 10th April Morning Slot Physics - Capacitor Question 101 English

40 $$\mu $$F and 10 $$\mu $$F

60 $$\mu $$F and 40 $$\mu $$F

20 $$\mu $$F and 30 $$\mu $$F

50 $$\mu $$F and 30 $$\mu $$F

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

The parallel combination of two air filled parallel plate capacitors of capacitance C and nC is connected to a battery of voltage, V. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitor. The new potential difference of the combined system is :-

$${V \over {K + n}}$$

$${{(n+1)V} \over {K + n}}$$

$${{nV} \over {K + n}}$$

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

Determine the charge on the capacitor in the following circuit :