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1
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which of the following figure represents the relation between Celsius and Fahrenheit temperatures?

A
JEE Main 2025 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 65 English Option 1
B
JEE Main 2025 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 65 English Option 2
C
JEE Main 2025 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 65 English Option 3
D
JEE Main 2025 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 65 English Option 4
2
JEE Main 2025 (Online) 24th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An ideal gas goes from an initial state to final state. During the process, the pressure of gas increases linearly with temperature.

A. The work done by gas during the process is zero.

B. The heat added to gas is different from change in its internal energy.

C. The volume of the gas is increased.

D. The internal energy of the gas is increased.

E. The process is isochoric (constant volume process)

Choose the correct answer from the options given below:

A
A, C Only
B
A, D, E Only
C
E Only
D
A, B, C, D Only
3
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
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Water of mass $m$ gram is slowly heated to increase the temperature from $T_1$ to $T_\gamma$. The change in entropy of the water, given specific heat of water is $1 \mathrm{Jkg}^{-1} \mathrm{~K}^{-1}$, is :

A
$\mathrm{m}\left(\mathrm{T}_2-\mathrm{T}_1\right)$
B
zero
C
$\mathrm{m} \ln \left(\frac{\mathrm{T}_1}{\mathrm{~T}_2}\right)$
D
$\mathrm{m} \ln \left(\frac{\mathrm{T}_2}{\mathrm{~T}_1}\right)$
4
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

JEE Main 2025 (Online) 23rd January Evening Shift Physics - Heat and Thermodynamics Question 70 English

Using the given $P-V$ diagram, the work done by an ideal gas along the path $A B C D$ is :

A
$3 \mathrm{P}_0 \mathrm{~V}_0$
B
$-3 \mathrm{P}_0 \mathrm{~V}_0$
C
$-4 \mathrm{P}_0 \mathrm{~V}_0$
D
$4 \mathrm{P}_0 \mathrm{~V}_0$

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