JEE Main 2023 (Online) 25th January Evening Shift | Heat and Thermodynamics Question 177 | Physics

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JEE Main 2023 (Online) 25th January Evening Shift

MCQ (Single Correct Answer)

-1

The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :-

JEE Main 2023 (Online) 25th January Evening Shift Physics - Heat and Thermodynamics Question 165 English

$${{{t_P}} \over {100}} = {{{t_Q} - 180} \over {150}}$$

$${{{t_P}} \over {180}} - {{{t_Q} - 40} \over {100}}$$

$${{{t_Q}} \over {150}} = {{{t_P} - 180} \over {100}}$$

$${{{t_Q}} \over {100}} = {{{t_P} - 30} \over {150}}$$

JEE Main 2023 (Online) 25th January Evening Shift

MCQ (Single Correct Answer)

-1

According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is :-

$$\frac{9}{2}R$$

$$\frac{5}{2}R$$

$$\frac{3}{2}R$$

$$\frac{7}{2}R$$

JEE Main 2023 (Online) 25th January Morning Shift

MCQ (Single Correct Answer)

-1

The root mean square velocity of molecules of gas is

Proportional to temperature ($$T$$)

Inversely proportional to square root of temperature $$\left( {\sqrt {{1 \over T}} } \right)$$

Proportional to square of temperature ($$T^2$$)

Proportional to square root of temperature ($$\sqrt T$$)

JEE Main 2023 (Online) 25th January Morning Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

A Carnot engine with efficiency 50% takes heat from a source at 600 K. In order to increase the efficiency to 70%, keeping the temperature of sink same, the new temperature of the source will be :

300 K

1000 K

900 K

360 K

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