JEE Main 2023 (Online) 1st February Morning Shift | Properties of Matter Question 61 | Physics

A mercury drop of radius $$10^{-3}~\mathrm{m}$$ is broken into 125 equal size droplets. Surface tension of mercury is $$0.45~\mathrm{Nm}^{-1}$$. The gain in surface energy is :

$$28\times10^{-5}~\mathrm{J}$$

$$17.5\times10^{-5}~\mathrm{J}$$

$$5\times10^{-5}~\mathrm{J}$$

$$2.26\times10^{-5}~\mathrm{J}$$

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

For a solid rod, the Young's modulus of elasticity is $3.2 \times 10^{11} \mathrm{Nm}^{-2}$ and density is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$. The velocity of longitudinal wave in the rod will be.

$3.65 \times 10^3 \mathrm{~ms}^{-1}$

$6.32 \times 10^3 \mathrm{~ms}^{-1}$

$18.96 \times 10^3 \mathrm{~ms}^{-1}$

$145.75 \times 10^3 \mathrm{~ms}^{-1}$

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

Under the same load, wire A having length $5.0 \mathrm{~m}$ and cross section $2.5 \times 10^{-5} \mathrm{~m}^{2}$ stretches uniformly by the same amount as another wire B of length $6.0 \mathrm{~m}$ and a cross section of $3.0 \times 10^{-5}$ $\mathrm{m}^{2}$ stretches. The ratio of the Young's modulus of wire A to that of wire $B$ will be :

$1: 2$

$1: 4$

$1: 1$

$1: 10$

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