1
JEE Main 2021 (Online) 20th July Evening Shift
Numerical
+4
-1
Potassium chlorate is prepared by electrolysis of KCl in basic solution as shown by following equation.
6OH$$-$$ + Cl$$-$$ $$\to$$ ClO3$$-$$ + 3H2O + 6e$$-$$
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is ____________. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol$$-$$1, F = 96500 C)
6OH$$-$$ + Cl$$-$$ $$\to$$ ClO3$$-$$ + 3H2O + 6e$$-$$
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is ____________. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol$$-$$1, F = 96500 C)
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2
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
+4
-1
The molar conductivities at infinite dilution of barium chloride, sulphuric acid and hydrochloric acid are 280, 860 and 426 S cm2 mol$$-$$1 respectively. The molar conductivity at infinite dilution of barium sulphate is _________ S cm2 mol$$-$$1. (Round off to the Nearest Integer ).
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3
JEE Main 2021 (Online) 18th March Morning Shift
Numerical
+4
-1
For the reaction
2Fe3+(aq) + 2I$$-$$(aq) $$ \to $$ 2Fe2+(aq) + I2(s)
the magnitude of the standard molar Gibbs free energy change, $$\Delta$$rG$$_m^o$$ = $$-$$ ___________ kJ (Round off to the Nearest Integer).
$$\left[ {\matrix{ {E_{F{e^{2 + }}/Fe(s)}^o = - 0.440V;} & {E_{F{e^{3 + }}/Fe(s)}^o = - 0.036V} \cr {E_{{I_2}/2{I^ - }}^o = 0.539V;} & {F = 96500C} \cr } } \right]$$
2Fe3+(aq) + 2I$$-$$(aq) $$ \to $$ 2Fe2+(aq) + I2(s)
the magnitude of the standard molar Gibbs free energy change, $$\Delta$$rG$$_m^o$$ = $$-$$ ___________ kJ (Round off to the Nearest Integer).
$$\left[ {\matrix{ {E_{F{e^{2 + }}/Fe(s)}^o = - 0.440V;} & {E_{F{e^{3 + }}/Fe(s)}^o = - 0.036V} \cr {E_{{I_2}/2{I^ - }}^o = 0.539V;} & {F = 96500C} \cr } } \right]$$
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4
JEE Main 2021 (Online) 17th March Evening Shift
Numerical
+4
-1
A KCl solution of conductivity 0.14 S m$$-$$1 shows a resistance of 4.19$$\Omega$$ in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to 1.03$$\Omega$$. The conductivity of the HCl solution is ____________ $$\times$$ 10$$-$$2 S m$$-$$1. (Round off to the Nearest Integer).
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