1
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For the reaction,

$$\mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{~g})$$

Attainment of equilibrium is predicted correctly by :

A
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 1
B
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 2
C
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 3
D
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 4
2
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the reaction

$$\mathrm{X}_2 \mathrm{Y}(\mathrm{~g}) \rightleftharpoons \mathrm{X}_2(\mathrm{~g})+\frac{1}{2} \mathrm{Y}_2(\mathrm{~g})$$

The equation representing correct relationship between the degree of dissociation (x) of $\mathrm{X}_2 \mathrm{Y}(\mathrm{g})$ with its equilibrium constant Kp is __________.

Assume $x$ to be very very small.

A
$x=\sqrt[3]{\frac{\mathrm{Kp}}{\mathrm{p}}}$
B
$x=\sqrt[3]{\frac{\mathrm{Kp}}{2 \mathrm{p}}}$
C
$x=\sqrt[3]{\frac{2 \mathrm{Kp}^2}{\mathrm{p}}}$
D
$x=\sqrt[3]{\frac{2 \mathrm{Kp}}{\mathrm{p}}}$
3
JEE Main 2025 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A vessel at 1000 K contains $\mathrm{CO}_2$ with a pressure of 0.5 atm . Some of $\mathrm{CO}_2$ is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm , then Kp is :

A
0.18 atm
B
0.3 atm
C
3 atm
D
1.8 atm
4
JEE Main 2024 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For the given hypothetical reactions, the equilibrium constants are as follows :

$$\begin{aligned} & \mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0 \\ & \mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0 \\ & \mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0 \end{aligned}$$

The equilibrium constant for the reaction $$\mathrm{X} \rightleftharpoons \mathrm{W}$$ is

A
12.0
B
8.0
C
6.0
D
7.0
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