1
JEE Main 2022 (Online) 24th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For a reaction at equilibrium

A(g) $$\rightleftharpoons$$ B(g) + $${1 \over 2}$$ C(g)

the relation between dissociation constant (K), degree of dissociation ($$\alpha$$) and equilibrium pressure (p) is given by :

A
$$K = {{{\alpha ^{{1 \over 2}}}{p^{{3 \over 2}}}} \over {{{\left( {1 + {3 \over 2}\alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}$$
B
$$K = {{{\alpha ^{{3 \over 2}}}{p^{{1 \over 2}}}} \over {{{\left( {2 + \alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}$$
C
$$K = {{{{(\alpha \,p)}^{{3 \over 2}}}} \over {{{\left( {1 + {3 \over 2}\alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}$$
D
$$K = {{{{(\alpha \,p)}^{{3 \over 2}}}} \over {{{\left( {1 + \alpha } \right)}}{{(1 - \alpha )}^{{1 \over 2}}}}}$$
2
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of KC is 64 at 800 K for the reaction

N2(g) + 3H2(g) ⇌ 2NH3(g)

The value of KC for the following reaction is :

NH3(g) ⇌ $${1 \over 2}$$N2(g) + $${3 \over 2}$$H2(g)
A
8
B
$${1 \over 8}$$
C
$${1 \over 4}$$
D
$${1 \over {64}}$$
3
JEE Main 2020 (Online) 6th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The variation of equilibrium constant with temperature is given below :

Temperature Equilibrium Constant
T1 = 25oC K1 = 10
T2 = 100oC K2 = 100

The values of $$\Delta $$Ho, $$\Delta $$Go at
T1 and $$\Delta $$Go at T2 (in kJ mol–1) respectively, are close to :
[Use R = 8.314 J K–1 mol–1]
A
28.4, –5.71 and –14.29
B
0.64, –7.14 and –5.71
C
28.4, –7.14 and –5.71
D
0.64, –5.71 and –14.29
4
JEE Main 2020 (Online) 6th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the reaction

Fe2N(s) + $${3 \over 2}$$H2(g) ⇌ 2Fe(s) + NH3(g)
A
KC = Kp(RT)1/2
B
KC = Kp(RT)-1/2
C
KC = Kp(RT)
D
KC = Kp(RT)3/2
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