1
JEE Main 2025 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

At temperature T, compound $AB_{2(g)}$ dissociates as $AB_{2(g)} \rightleftharpoons AB_{(g)} + \frac{1}{2} B_{2(g)}$ having degree of dissociation $ x $ (small compared to unity). The correct expression for $ x $ in terms of $ K_p $ and $ p $ is:

A

$ \sqrt{K_p} $

B
$\sqrt[3]{\frac{2 K_{\mathrm{p}}^2}{\mathrm{p}}}$
C
$\sqrt[3]{\frac{2 K_p}{p}}$
D
$\sqrt[4]{\frac{2 K_p}{p}}$
2
JEE Main 2025 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For the reaction,

$$\mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{~g})$$

Attainment of equilibrium is predicted correctly by :

A
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 1
B
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 2
C
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 3
D
JEE Main 2025 (Online) 24th January Evening Shift Chemistry - Chemical Equilibrium Question 6 English Option 4
3
JEE Main 2025 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the reaction

$$\mathrm{X}_2 \mathrm{Y}(\mathrm{~g}) \rightleftharpoons \mathrm{X}_2(\mathrm{~g})+\frac{1}{2} \mathrm{Y}_2(\mathrm{~g})$$

The equation representing correct relationship between the degree of dissociation (x) of $\mathrm{X}_2 \mathrm{Y}(\mathrm{g})$ with its equilibrium constant Kp is __________.

Assume $x$ to be very very small.

A
$x=\sqrt[3]{\frac{\mathrm{Kp}}{\mathrm{p}}}$
B
$x=\sqrt[3]{\frac{\mathrm{Kp}}{2 \mathrm{p}}}$
C
$x=\sqrt[3]{\frac{2 \mathrm{Kp}^2}{\mathrm{p}}}$
D
$x=\sqrt[3]{\frac{2 \mathrm{Kp}}{\mathrm{p}}}$
4
JEE Main 2025 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A vessel at 1000 K contains $\mathrm{CO}_2$ with a pressure of 0.5 atm . Some of $\mathrm{CO}_2$ is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm , then Kp is :

A
0.18 atm
B
0.3 atm
C
3 atm
D
1.8 atm
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