1
JEE Main 2020 (Online) 4th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the equilibrium constant for
A ⇌ B + C is $$K_{eq}^{(1)}$$ and that of
B + C ⇌ P is $$K_{eq}^{(2)}$$, the equilibrium
constant for A ⇌ P is :
A
$${{K_{eq}^{(1)}} \over {K_{eq}^{(2)}}}$$
B
$${K_{eq}^{(1)}}$$ + $${K_{eq}^{(2)}}$$
C
$${K_{eq}^{(2)}}$$ - $${K_{eq}^{(1)}}$$
D
$${K_{eq}^{(1)}}$$ $${K_{eq}^{(2)}}$$
2
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the equilibrium A ⇌ B , the variation of the rate of the forward (a) and reverse (b) reaction with time is given by :
A
JEE Main 2020 (Online) 4th September Morning Slot Chemistry - Chemical Equilibrium Question 60 English Option 1
B
JEE Main 2020 (Online) 4th September Morning Slot Chemistry - Chemical Equilibrium Question 60 English Option 2
C
JEE Main 2020 (Online) 4th September Morning Slot Chemistry - Chemical Equilibrium Question 60 English Option 3
D
JEE Main 2020 (Online) 4th September Morning Slot Chemistry - Chemical Equilibrium Question 60 English Option 4
3
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An open beaker of water in equilibrium with water vapour is in a sealed container. When a few grams of glucose are added to the beaker of water, the rate at which water molecules :
A
leaves the solution increases
B
leaves the vapour increases
C
leaves the vapour decreases
D
leaves the solution decreases
4
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the figure shown below reactant A (represented by square) is in equilibrium with product B (represented by circle). The equilibrium constant is : JEE Main 2020 (Online) 9th January Evening Slot Chemistry - Chemical Equilibrium Question 62 English
A
1
B
2
C
8
D
4
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