1
JEE Main 2024 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Let $$f:(-\infty, \infty)-\{0\} \rightarrow \mathbb{R}$$ be a differentiable function such that $$f^{\prime}(1)=\lim _\limits{a \rightarrow \infty} a^2 f\left(\frac{1}{a}\right)$$. Then $$\lim _\limits{a \rightarrow \infty} \frac{a(a+1)}{2} \tan ^{-1}\left(\frac{1}{a}\right)+a^2-2 \log _e a$$ is equal to

A
$$\frac{5}{2}+\frac{\pi}{8}$$
B
$$\frac{3}{8}+\frac{\pi}{4}$$
C
$$\frac{3}{4}+\frac{\pi}{8}$$
D
$$\frac{3}{2}+\frac{\pi}{4}$$
2
JEE Main 2024 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

$$\int_\limits0^{\pi / 4} \frac{\cos ^2 x \sin ^2 x}{\left(\cos ^3 x+\sin ^3 x\right)^2} d x \text { is equal to }$$

A
1/9
B
1/6
C
1/3
D
1/12
3
JEE Main 2024 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

The mean and standard deviation of 20 observations are found to be 10 and 2 , respectively. On rechecking, it was found that an observation by mistake was taken 8 instead of 12. The correct standard deviation is

A
1.94
B
$$\sqrt{3.96}$$
C
$$\sqrt{3.86}$$
D
1.8
4
JEE Main 2024 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Let $$y=y(x)$$ be the solution of the differential equation $$\left(1+x^2\right) \frac{d y}{d x}+y=e^{\tan ^{-1} x}$$, $$y(1)=0$$. Then $$y(0)$$ is

A
$$\frac{1}{4}\left(e^{\pi / 2}-1\right)$$
B
$$\frac{1}{2}\left(1-e^{\pi / 2}\right)$$
C
$$\frac{1}{4}\left(1-e^{\pi / 2}\right)$$
D
$$\frac{1}{2}\left(e^{\pi / 2}-1\right)$$
JEE Main Papers
2023
2021
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
CBSE
Class 12