1
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
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JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Basics of Organic Chemistry Question 3 English

The correct arrangement for decreasing order of electrophilic substitution for above compounds is :

A
$$\text { (III) }>\text { (IV) }>\text { (II) }>\text { (I) }$$
B
$$\text { (III) }>\text { (I) }>\text { (II) }>\text { (IV) }$$
C
$$\text { (II) }>\text { (IV) }>\text { (III) }>\text { (I) }$$
D
$$(\text { IV) }>\text { (I) }>\text { (II) }>\text { (III) }$$
2
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
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During the detection of acidic radical present in a salt, a student gets a pale yellow precipitate soluble with difficulty in $$\mathrm{NH}_4 \mathrm{OH}$$ solution when sodium carbonate extract was first acidified with dil. $$\mathrm{HNO}_3$$ and then $$\mathrm{AgNO}_3$$ solution was added. This indicates presence of :

A
$$\mathrm{I}^{-}$$
B
$$\mathrm{CO}_3{ }^{2-}$$
C
$$\mathrm{Cl}^{-}$$
D
$$\mathrm{Br}^{-}$$
3
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
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Consider the given reaction, identify the major product P.

JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 2 English

A
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 2 English Option 1
B
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 2 English Option 2
C
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 2 English Option 3
D
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 2 English Option 4
4
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II.

LIST I
Reaction
LIST II
Type of redox reaction
A. $$
\mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})}
$$
I. Decomposition
B. $$
2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \rightarrow 2 \mathrm{PbO}_{(\mathrm{s})}+4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}
$$
II. Displacement
C. $$
2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow 2 \mathrm{NaOH}_{(\mathrm{aq} .)}+\mathrm{H}_{2(\mathrm{~g})}
$$
III. Disproportionation
D. $$
2 \mathrm{NO}_{2(\mathrm{~g})}+2^{-} \mathrm{OH}(\text { aq. }) \rightarrow \mathrm{NO}_{2(\mathrm{aq} .)}^{-}+\mathrm{NO}_{3(\text { aq. })}^{-}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}
$$
IV. Combination

Choose the correct answer from the options given below :

A
(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
B
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
C
(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
D
(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
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