1
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Arrange the following elements in the increasing order of number of unpaired electrons in it.

(A) $$\mathrm{Sc}$$

(B) $$\mathrm{Cr}$$

(C) $$\mathrm{V}$$

(D) $$\mathrm{Ti}$$

(E) $$\mathrm{Mn}$$

Choose the correct answer from the options given below :

A
$$ (\mathrm{A})<(\mathrm{D})<(\mathrm{C})<(\mathrm{B})<(\mathrm{E}) $$
B
$$ (\mathrm{A})<(\mathrm{D})<(\mathrm{C})<(\mathrm{E})<(\mathrm{B}) $$
C
$$ (\mathrm{B})<(\mathrm{C})<(\mathrm{D})<(\mathrm{E})<(\mathrm{A}) $$
D
$$ (\mathrm{C})<(\mathrm{E})<(\mathrm{B})<(\mathrm{A})<(\mathrm{D}) $$
2
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The major products formed :

JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 9 English

A and B respectively are :

A
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 9 English Option 1
B
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 9 English Option 2
C
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 9 English Option 3
D
JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 9 English Option 4
3
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The incorrect statements regarding enzymes are :

(A) Enzymes are biocatalysts.

(B) Enzymes are non-specific and can catalyse different kinds of reactions.

(C) Most Enzymes are globular proteins.

(D) Enzyme - oxidase catalyses the hydrolysis of maltose into glucose.

Choose the correct answer from the option given below :

A
(B) and (D)
B
(A), (B) and (C)
C
(B) and (C)
D
(B), (C) and (D)
4
JEE Main 2024 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The ratio $$\frac{K_P}{K_C}$$ for the reaction :

$$\mathrm{CO}_{(\mathrm{g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons \mathrm{CO}_{2(\mathrm{~g})}$$ is :

A
1
B
$$ (\mathrm{RT})^{1 / 2} $$
C
RT
D
$$\mathrm{ \frac{1}{\sqrt{R T}}} $$
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