1
JEE Main 2024 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

The equation of stationary wave is :

$$y=2 \mathrm{a} \sin \left(\frac{2 \pi \mathrm{nt}}{\lambda}\right) \cos \left(\frac{2 \pi x}{\lambda}\right) \text {. }$$

Which of the following is NOT correct :

A
The dimensions of $$\mathrm{nt}$$ is [L]
B
The dimensions of $$n$$ is $$[\mathrm{LT}^{-1}]$$
C
The dimensions of $$x$$ is [L]
D
The dimensions of $$n / \lambda$$ is [T]
2
JEE Main 2024 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Which figure shows the correct variation of applied potential difference (V) with photoelectric current (I) at two different intensities of light $$(\mathrm{I}_1<\mathrm{I}_2)$$ of same wavelengths :

A
JEE Main 2024 (Online) 4th April Morning Shift Physics - Dual Nature of Radiation Question 10 English Option 1
B
JEE Main 2024 (Online) 4th April Morning Shift Physics - Dual Nature of Radiation Question 10 English Option 2
C
JEE Main 2024 (Online) 4th April Morning Shift Physics - Dual Nature of Radiation Question 10 English Option 3
D
JEE Main 2024 (Online) 4th April Morning Shift Physics - Dual Nature of Radiation Question 10 English Option 4
3
JEE Main 2024 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

P-T diagram of an ideal gas having three different densities $$\rho_1, \rho_2, \rho_3$$ (in three different cases) is shown in the figure. Which of the following is correct :

JEE Main 2024 (Online) 4th April Morning Shift Physics - Heat and Thermodynamics Question 16 English

A
$$\rho_1>\rho_2$$
B
$$\rho_2<\rho_3$$
C
$$\rho_1=\rho_2=\rho_3$$
D
$$\rho_1<\rho_2$$
4
JEE Main 2024 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1

The electric field in an electromagnetic wave is given by $$\overrightarrow{\mathrm{E}}=\hat{i} 40 \cos \omega(\mathrm{t}-z / \mathrm{c}) \mathrm{NC}^{-1}$$. The magnetic field induction of this wave is (in SI unit) :

A
$$\overrightarrow{\mathrm{B}}=\hat{j} \frac{40}{\mathrm{c}} \cos \omega(\mathrm{t}-z / \mathrm{c})$$
B
$$\overrightarrow{\mathrm{B}}=\hat{i} \frac{40}{\mathrm{c}} \cos \omega(\mathrm{t}-z / \mathrm{c})$$
C
$$\vec{B}=\hat{j} 40 \cos \omega(t-z / c)$$
D
$$\overrightarrow{\mathrm{B}}=\hat{k} \frac{40}{\mathrm{c}} \cos \omega(\mathrm{t}-z / \mathrm{c})$$
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