1
JEE Main 2024 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II

LIST I LIST II
A. Purely capacitive circuit I. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 19 English 1
B. Purely inductive circuit II. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 19 English 2
C. LCR series at resonance III. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 19 English 3
D. LCR series circuit IV. JEE Main 2024 (Online) 4th April Evening Shift Physics - Alternating Current Question 19 English 4

Choose the correct answer from the options given below:

A
A-IV. B-I, C-III, D-II
B
A-I. B-IV, C-II, D-III
C
A-IV. B-I, C-II, D-III
D
A-I. B-IV, C-III, D-II
2
JEE Main 2024 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which of the diode circuit shows correct biasing used for the measurement of dynamic resistance of p-n junction diode :

A
JEE Main 2024 (Online) 4th April Evening Shift Physics - Semiconductor Question 26 English Option 1
B
JEE Main 2024 (Online) 4th April Evening Shift Physics - Semiconductor Question 26 English Option 2
C
JEE Main 2024 (Online) 4th April Evening Shift Physics - Semiconductor Question 26 English Option 3
D
JEE Main 2024 (Online) 4th April Evening Shift Physics - Semiconductor Question 26 English Option 4
3
JEE Main 2024 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A sample of gas at temperature $$T$$ is adiabatically expanded to double its volume. Adiabatic constant for the gas is $$\gamma=3 / 2$$. The work done by the gas in the process is:

$$(\mu=1 \text { mole })$$

A
$$R T[2 \sqrt{2}-1]$$
B
$$R T[2-\sqrt{2}]$$
C
$$R T[1-2 \sqrt{2}]$$
D
$$R T[\sqrt{2}-2]$$
4
JEE Main 2024 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The magnetic moment of a bar magnet is $$0.5 \mathrm{~Am}^2$$. It is suspended in a uniform magnetic field of $$8 \times 10^{-2} \mathrm{~T}$$. The work done in rotating it from its most stable to most unstable position is:

A
$$4 \times 10^{-2} \mathrm{~J}$$
B
$$16 \times 10^{-2} \mathrm{~J}$$
C
$$8 \times 10^{-2} \mathrm{~J}$$
D
Zero
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