1
JEE Main 2024 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A stone of mass $$900 \mathrm{~g}$$ is tied to a string and moved in a vertical circle of radius $$1 \mathrm{~m}$$ making $$10 \mathrm{~rpm}$$. The tension in the string, when the stone is at the lowest point is (if $$\pi^2=9.8$$ and $$g=9.8 \mathrm{~m} / \mathrm{s}^2$$) :

A
17.8 N
B
97 N
C
9.8 N
D
8.82 N
2
JEE Main 2024 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The truth table for this given circuit is :

JEE Main 2024 (Online) 29th January Evening Shift Physics - Semiconductor Question 15 English

A
JEE Main 2024 (Online) 29th January Evening Shift Physics - Semiconductor Question 15 English Option 1
B
JEE Main 2024 (Online) 29th January Evening Shift Physics - Semiconductor Question 15 English Option 2
C
JEE Main 2024 (Online) 29th January Evening Shift Physics - Semiconductor Question 15 English Option 3
D
JEE Main 2024 (Online) 29th January Evening Shift Physics - Semiconductor Question 15 English Option 4
3
JEE Main 2024 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A bob of mass '$$m$$' is suspended by a light string of length '$$L$$'. It is imparted a minimum horizontal velocity at the lowest point $$A$$ such that it just completes half circle reaching the top most position B. The ratio of kinetic energies $$\frac{(K . E)_A}{(K . E)_B}$$ is :

JEE Main 2024 (Online) 29th January Evening Shift Physics - Work Power & Energy Question 13 English

A
5 : 1
B
3 : 2
C
1 : 5
D
2 : 5
4
JEE Main 2024 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An electric field is given by $$(6 \hat{i}+5 \hat{j}+3 \hat{k}) \mathrm{N} / \mathrm{C}$$. The electric flux through a surface area $$30 \hat{i} \mathrm{~m}^2$$ lying in YZ-plane (in SI unit) is :

A
60
B
90
C
180
D
150
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