1
JEE Main 2023 (Online) 29th January Evening Shift
Numerical
+4
-1
Change Language

At 298 K

$$\mathrm{N_2~(g)+3H_2~(g)\rightleftharpoons~2NH_3~(g),~K_1=4\times10^5}$$

$$\mathrm{N_2~(g)+O_2~(g)\rightleftharpoons~2NO~(g),~K_2=1.6\times10^{12}}$$

$$\mathrm{H_2~(g)+\frac{1}{2}O_2~(g)\rightleftharpoons~H_2O~(g),~K_3=1.0\times10^{-13}}$$

Based on above equilibria, then equilibrium constant of the reaction, $$\mathrm{2NH_3(g)+\frac{5}{2}O_2~(g)\rightleftharpoons~2NO~(g)+3H_2O~(g)}$$ is ____________ $$\times10^{-33}$$ (Nearest integer).

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2
JEE Main 2023 (Online) 29th January Evening Shift
Numerical
+4
-1
Out of Syllabus
Change Language

A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is _________ $$\times$$ $$10^{21}$$ (Nearest integer).

(Given $$\mathrm{N_A=6.02\times10^{23}}$$)

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3
JEE Main 2023 (Online) 29th January Evening Shift
Numerical
+4
-1
Change Language

The denticity of the ligand present in the Fehling's reagent is ___________.

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4
JEE Main 2023 (Online) 29th January Evening Shift
Numerical
+4
-1
Change Language

When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of CO$$_2$$ was produced. The molar mass of compound is _____________ g mol$$^{-1}$$ (Nearest integer).

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