1
JEE Main 2023 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements :

Statement I : Electromagnetic waves are not deflected by electric and magnetic field.

Statement II : The amplitude of electric field and the magnetic field in electromagnetic waves are related to each other as $${E_0} = \sqrt {{{{\mu _0}} \over {{\varepsilon _0}}}} {B_0}$$.

In the light of the above statements, choose the correct answer from the options given below :

A
Both Statement I and Statement II are true
B
Statement I is true and Statement II is false
C
Both Statement I and Statement II are false
D
Statement I is false but Statement II is true
2
JEE Main 2023 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The time taken by an object to slide down 45$$^\circ$$ rough inclined plane is n times as it takes to slide down a perfectly smooth 45$$^\circ$$ incline plane. The coefficient of kinetic friction between the object and the incline plane is :

A
$$1 - {1 \over {{n^2}}}$$
B
$$1 + {1 \over {{n^2}}}$$
C
$$\sqrt {1 - {1 \over {{n^2}}}} $$
D
$$\sqrt {{1 \over {1 - {n^2}}}} $$
3
JEE Main 2023 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For the given figures, choose the correct options :

JEE Main 2023 (Online) 29th January Evening Shift Physics - Alternating Current Question 35 English

A
The rms current in circuit (b) can be larger than that in (a)
B
The rms current in figure (a) is always equal to that in figure (b)
C
The rms current in circuit (b) can never be larger than that in (a)
D
At resonance, current in (b) is less than that in (a)
4
JEE Main 2023 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An object moves at a constant speed along a circular path in a horizontal plane with center at the origin. When the object is at $$x=+2~\mathrm{m}$$, its velocity is $$\mathrm{ - 4\widehat j}$$ m/s. The object's velocity (v) and acceleration (a) at $$x=-2~\mathrm{m}$$ will be

A
$$v=4\mathrm{\widehat i~m/s},a=8\mathrm{\widehat j~m/s^2}$$
B
$$v=4\mathrm{\widehat j~m/s},a=8\mathrm{\widehat i~m/s^2}$$
C
$$v=-4\mathrm{\widehat i~m/s},a=-8\mathrm{\widehat j~m/s^2}$$
D
$$v=-4\mathrm{\widehat j~m/s},a=8\mathrm{\widehat i~m/s^2}$$
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