1
JEE Main 2023 (Online) 25th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match the List-I with List-II :

List-I
Cations
List-II
Group reagents
A. $$\mathrm{Pb^{2+},Cu^{2+}}$$ i) $$\mathrm{H_2S}$$ gas in presence of dilute HCl
B. $$\mathrm{Al^{3+},Fe^{3+}}$$ ii) $$\mathrm{(NH_4)_2CO_3}$$ in presence of $$\mathrm{NH_4OH}$$
C. $$\mathrm{Co^{2+},Ni^{2+}}$$ iii) $$\mathrm{NH_4OH}$$ in presence of $$\mathrm{NH_4Cl}$$
D. $$\mathrm{Ba^{2+},Ca^{2+}}$$ iv) H2S in presence of NH4OH

Correct match is -

A
A $$\to$$ i, B $$\to$$ iii, C $$\to$$ iv, D $$\to$$ ii
B
A $$\to$$ i, B $$\to$$ iii, C $$\to$$ ii, D $$\to$$ iv
C
A $$\to$$ iii, B $$\to$$ i, C $$\to$$ iv, D $$\to$$ ii
D
A $$\to$$ iv, B $$\to$$ ii, C $$\to$$ iii, D $$\to$$ i
2
JEE Main 2023 (Online) 25th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

Compound A reacts with NH$$_4$$Cl and forms a compound B. Compound B reacts with H$$_2$$O and excess of CO$$_2$$ to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A, B and C, are respectively :

A
$$\mathrm{Ca{(OH)_2},NH_4^ \oplus ,{(N{H_4})_2}C{O_3}}$$
B
$$\mathrm{CaC{l_2},NH_4^ \oplus ,{(N{H_4})_2}C{O_3}}$$
C
$$\mathrm{CaC{l_2},N{H_3},N{H_4}HC{O_3}}$$
D
$$\mathrm{Ca{(OH)_2},N{H_3},N{H_4}HC{O_3}}$$
3
JEE Main 2023 (Online) 25th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate corner and one at the center of cube. Y is at $$\frac{1}{3}^{\mathrm{rd}}$$ of the total faces. The empirical formula of the compound is :

A
$$\mathrm{{X_2}{Y_{1.5}}}$$
B
$$\mathrm{{X_{3}}{Y_2}}$$
C
$$\mathrm{X{Y_{2.5}}}$$
D
$$\mathrm{{X_{2.5}}Y}$$
4
JEE Main 2023 (Online) 25th January Morning Shift
Numerical
+4
-1
Change Language

The density of a monobasic strong acid (Molar mass 24.2 g/mol) is 1.21 kg/L. The volume of its solution required for the complete neutralization of 25 mL of 0.24 M NaOH is __________ $$\times$$ 10$$^{-2}$$ mL (Nearest integer)

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