1
JEE Main 2022 (Online) 28th June Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let f : R $$\to$$ R be a continuous function satisfying f(x) + f(x + k) = n, for all x $$\in$$ R where k > 0 and n is a positive integer. If $${I_1} = \int\limits_0^{4nk} {f(x)dx} $$ and $${I_2} = \int\limits_{ - k}^{3k} {f(x)dx} $$, then :

A
$${I_1} + 2{I_2} = 4nk$$
B
$${I_1} + 2{I_2} = 2nk$$
C
$${I_1} + n{I_2} = 4{n^2}k$$
D
$${I_1} + n{I_2} = 6{n^2}k$$
2
JEE Main 2022 (Online) 28th June Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The area of the bounded region enclosed by the curve

$$y = 3 - \left| {x - {1 \over 2}} \right| - |x + 1|$$ and the x-axis is :

A
$${9 \over 4}$$
B
$${45 \over 16}$$
C
$${27 \over 8}$$
D
$${63 \over 16}$$
3
JEE Main 2022 (Online) 28th June Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let x = x(y) be the solution of the differential equation

$$2y\,{e^{x/{y^2}}}dx + \left( {{y^2} - 4x{e^{x/{y^2}}}} \right)dy = 0$$ such that x(1) = 0. Then, x(e) is equal to :

A
$$e{\log _e}(2)$$
B
$$ - e{\log _e}(2)$$
C
$${e^2}{\log _e}(2)$$
D
$$ - {e^2}{\log _e}(2)$$
4
JEE Main 2022 (Online) 28th June Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let the slope of the tangent to a curve y = f(x) at (x, y) be given by 2 $$\tan x(\cos x - y)$$. If the curve passes through the point $$\left( {{\pi \over 4},0} \right)$$, then the value of $$\int\limits_0^{\pi /2} {y\,dx} $$ is equal to :

A
$$(2 - \sqrt 2 ) + {\pi \over {\sqrt 2 }}$$
B
$$2 - {\pi \over {\sqrt 2 }}$$
C
$$(2 + \sqrt 2 ) + {\pi \over {\sqrt 2 }}$$
D
$$2 + {\pi \over {\sqrt 2 }}$$
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