1
JEE Main 2022 (Online) 27th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
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Given below are two statements: one is labelled as Assertion A and, the other is labelled as Reason R.

Assertion A: [6] Annulene, [8] Annulene and cis-[10] Annulene, are respectively aromatic, not-aromatic and aromatic.

JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Basics of Organic Chemistry Question 121 English

Reason R: Planarity is one of the requirements of aromatic systems.

In the light of the above statements, choose the most appropriate answer from the options given below.

A
Both A and R are correct and R is the correct explanation of A.
B
Both A and R are correct but R is NOT the correct explanation of A.
C
A is correct but R is not correct.
D
A is not correct but R is correct.
2
JEE Main 2022 (Online) 27th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
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JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 67 English

In the above reaction product B is :

A
JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 67 English Option 1
B
JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 67 English Option 2
C
JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 67 English Option 3
D
JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 67 English Option 4
3
JEE Main 2022 (Online) 27th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A sugar 'X' dehydrates very slowly under acidic condition to give furfural which on further reaction with resorcinol gives the coloured product after sometime. Sugar 'X' is

A
Aldopentose
B
Aldotetrose
C
Oxalic acid
D
Ketotetrose
4
JEE Main 2022 (Online) 27th July Morning Shift
MCQ (Single Correct Answer)
+4
-1
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In Carius method of estimation of halogen, $$0.45 \mathrm{~g}$$ of an organic compound gave $$0.36 \mathrm{~g}$$ of $$\mathrm{AgBr}$$. Find out the percentage of bromine in the compound.

(Molar masses : $$\mathrm{AgBr}=188 \mathrm{~g} \mathrm{~mol}^{-1} ; \mathrm{Br}=80 \mathrm{~g} \mathrm{~mol}^{-1}$$)

A
34.04%
B
40.04%
C
36.03%
D
38.04%
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