1
JEE Main 2022 (Online) 25th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be : (Given g = acceleration due to gravity at the surface of earth).

A
g/2
B
g/4
C
g/3
D
g/9
2
JEE Main 2022 (Online) 25th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The terminal velocity (vt) of the spherical rain drop depends on the radius (r) of the spherical rain drop as :

A
r1/2
B
r
C
r2
D
r3
3
JEE Main 2022 (Online) 25th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The relation between root mean square speed (vrms) and most probable sped (vp) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :

A
$${v_{rms}} = \sqrt {{2 \over 3}} {v_p}$$
B
$${v_{rms}} = \sqrt {{3 \over 2}} {v_p}$$
C
$${v_{rms}} = {v_p}$$
D
$${v_{rms}} = \sqrt {{1 \over 3}} {v_p}$$
4
JEE Main 2022 (Online) 25th June Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In the figure, a very large plane sheet of positive charge is shown. P1 and P2 are two points at distance l and 2l from the charge distribution. If $$\sigma$$ is the surface charge density, then the magnitude of electric fields E1 and E2 at P1 and P2 respectively are :

JEE Main 2022 (Online) 25th June Morning Shift Physics - Electrostatics Question 74 English

A
$${E_1} = \sigma /{\varepsilon _0},\,{E_2} = \sigma /2{\varepsilon _0}$$
B
$${E_1} = 2\sigma /{\varepsilon _0},\,{E_2} = \sigma /{\varepsilon _0}$$
C
$${E_1} = {E_2} = \sigma /2{\varepsilon _0}$$
D
$${E_1} = {E_2} = \sigma /{\varepsilon _0}$$
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