1
JEE Main 2020 (Online) 4th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
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On the x-axis and at a distance x from the origin, the gravitational field due a mass distribution is given by $${{Ax} \over {{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}}$$ in the x-direction. The magnitude of gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity, is:
A
$${A{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}$$
B
$${A{{\left( {{x^2} + {a^2}} \right)}^{1/2}}}$$
C
$${A \over {{{\left( {{x^2} + {a^2}} \right)}^{1/2}}}}$$
D
$${A \over {{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}}$$
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